$E:\vec x = \vek{2}{-2}{1} + r\vek{1}{1}{-2} + s\vek{1}{2}{-3}$
In der $x_2x_3$-Ebene gilt $x_1=0$
Also: $0=2+1r+1s \ra s = -r-2$
einsetzen in $E$:
$ \vek{2}{-2}{1} + r\vek{1}{1}{-2} + (-r-2)\vek{1}{2}{-3}$
$=\vek{2}{-2}{1} + r\vek{1}{1}{-2} -r\vek{1}{2}{-3} -2\vek{1}{2}{-3}$
$=\vek{2}{-2}{1}-\vek24{-6} + r\left(\vek{1}{1}{-2} +\vek{-1}{-2}{3}\right)$
$=\vek{0}{-6}{7} + r\vek{0}{-1}{1} $